Solution — Cs50 Tideman

ranks[rank] = i; return true;

Once the graph is locked, the winner is the candidate with no incoming edges (the source of the graph). Cs50 Tideman Solution

: if there is a candidate who would win every head-to-head matchup against every other candidate, that person must win the election. The Problem with Plurality ranks[rank] = i; return true; Once the graph

Here’s a helpful, explanatory text for understanding and implementing the Tideman problem from CS50 (the “locked pairs” voting method). It’s not the full code, but a reasoning guide to help you write your own solution. ranks[rank] = i

Locked: Alice→Bob, Bob→Charlie. Testing Charlie→Alice: Start from loser (Alice? No! loser is the second arg? Careful.)

Pairs sorted: (A,B,margin=5), (B,C,margin=4), (C,A,margin=3)

The Tideman algorithm would then: