Find ([Cl^-]) when ([Ag^+] = 1.0\times 10^-5) M (complete precipitation): [ [Cl^-] = \fracK_sp(AgCl)[Ag^+] \textfinal = \frac1.8\times 10^-101.0\times 10^-5 = 1.8\times 10^-5 \text M ] At this ([Cl^-]), check if (PbCl_2) has started: (Q = [Pb^2+][Cl^-]^2 = (0.10)(1.8\times 10^-5)^2 = 3.24\times 10^-11) Compare to (K sp(PbCl_2) = 1.7\times 10^-5). (Q \ll K_sp), so (Pb^2+) is still in solution. Separation is possible.